Probability
Once when stepping out of home in the night to buy bread from downstairs, I wondered what would be the odds of me crossing paths with my dad who would be on his way home from work.
This presents an interesting probability puzzle which I have laid out below.
Assume I have to go from A to C and my dad has to go from B to A as per the diagram above. I am equally likely to take the route ADGFC or the route ADEFC. My dad will always take the BGDA route. My dad walks at 100 meters/min while I walk at 125 meters/min. What is the probability of us meeting on the way if my dad is equally likely to start from B anytime between 9.00 pm and 9.30 pm and I am equally likely to start A at any time between 9.10 pm and 9.20 pm?
Treat assured to the first correct answer... :)
posted by Slim at
2:30 PM
6 Comments:
0.
(Both of you are starting on different days)
By
musketeer, at 7:04 PM, August 21, 2009
Thats a good creative answer and u get a treat for that. But the floor is still open for the mathematically correct one (assuming we start on the same day!) :)
By
Slim, at 9:01 PM, August 21, 2009
This comment has been removed by the author.
By
Shantanu, at 1:53 AM, August 22, 2009
http://shantanugangal.blogspot.com/2009/08/probability.html
Couldn't post an image within a comment.
By
Shantanu, at 1:55 AM, August 22, 2009
Well done. Expected from CAT topper! :D
By
Slim, at 11:05 AM, August 22, 2009
Thanks. And the treat ? :P
By
Shantanu, at 12:58 AM, August 23, 2009
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